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How do you graph 7y is less than or equal to 112 plus 2x?

User Jakob Em
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1 Answer

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This shaded area represents the region where y is less than or equal to 16 + (2/7)x.

How to solve

To graph the inequality 7y ≤ 112 + 2x, follow these steps:

Rewrite the inequality in slope-intercept form:

y ≤ 16 + (2/7)x

Identify the slope and y-intercept:

Slope: 2/7

Y-intercept: 16

Draw the appropriate y- and x-axis labels.

Plot the y-intercept:

Place a point at (0, 16) on the graph.

Use the slope to find additional points:

From the y-intercept (0, 16), move 2 positions up and 7 positions to the right to locate another point on the line. This point would be (7, 18).

Draw a dotted line passing through the y-intercept and the additional point:

Since the inequality is ≤, use a dotted line to indicate that the line represents the boundary, but points on the line and below the line are solutions.

Shade the area below the dotted line:

This shaded area represents the region where y is less than or equal to 16 + (2/7)x.

How do you graph 7y is less than or equal to 112 plus 2x?-example-1
User Lamond
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