Question

We are going to take each reactant to grams of CO2 (g). So let's first take the 10.0 g CH4 (g) to g of CO2 (g). We already know the molar mass of CH4 (g) is 16.05 g/mol, but what is the mole ratio of CH4 (g) to CO2 (g)? 1 mol CH4 (g) /2 mol CO2 (g) 1 mol CH4 (g) /3 mol CO2 (g) 1 mol CH4 (g) /1 mol CO2 (g) 2 mol CH4 (g) /1 mol CO2 (g)

Answer 1

The mole ratio of CH4 (g) to CO2 (g) during the combustion of methane is 1 mol CH4 (g) to 1 mol CO2 (g), based on the balanced chemical equation for the reaction.

Step-by-step explanation:

To determine the mole ratio of CH4 (g) to CO2 (g) during the combustion of methane, we can refer to the balanced chemical equation:

CH4(g) + 2O2(g) → CO₂(g) + 2H₂O(l)

According to this equation, for each mole of CH4 (g) that reacts, one mole of CO2 (g) is produced. Therefore, the mole ratio of CH4 to CO2 is 1 mol CH4 (g) to 1 mol CO2 (g).