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26 votes
26 votes
If f(x)=(-x)^3-x^2-x+15How do I find f(2)+f(-2) = to?

User ChimeraObscura
by
2.6k points

1 Answer

20 votes
20 votes

Given:

There are given the function:


f(x)=(-x)^3-x^2-x+15

Step-by-step explanation:

From the given operation:


f(2)+f(-2)

Then,

First, we need to find the value of f(2):

Then,

To find the value of f(2), we need to put 2 for x into the given function:


\begin{gathered} f(x)=(-x)^(3)-x^(2)-x+15 \\ f(x)=(-2)^3-2^2-2+15 \\ f(x)=-8-4-2+15 \\ f(x)=-14+15 \\ f(x)=1 \end{gathered}

And,

We need to find the value for f(-2).

So,

Put -2 for x into the given function:

Then,


\begin{gathered} f(x)=(-x)^(3)-x^(2)-x+15 \\ f(-2)=(-(-2))^3-(-2)^2-(-2)+15 \\ f(-2)=8-4+2+15 \\ f(-2)=21 \end{gathered}

Then,


\begin{gathered} f(2)+f(-2)=1+21 \\ =22 \end{gathered}

Final answer:

Hence, the correct option is 22.

User Goombah
by
3.1k points
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