Question

4 mi.

What is the length of the hypotenuse? If necessary, r
C =
Submit
5 mi.
miles

Answer 1

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \end{array} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{4}\\ o=\stackrel{opposite}{5} \end{cases} \\\\\\ c=√( 4^2 + 5^2)\implies c=√( 16 + 25 ) \implies c=√( 41 )\implies c\approx 6.40`