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An urban planner drew a map of his town. On the map, 2 inches represents 3 miles. The table shows distances on the map and actual distances. Complete the table.

A table with two columns and four rows. The first column title is Map Distance in inches. The second column title is Actual Distance in miles. The first row has two inches and three miles. The second row has five inches and seven and five-tenths miles. The third row has twelve inches and unknown miles. The fourth row has twenty inches and unknown miles.

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A table with two columns and four rows. The first column title is Map Distance in inches. The second column title is Actual Distance in miles.

| Map Distance (in inches) | Actual Distance (in miles) |
|-------------------------|---------------------------|
| 2 | 3 |
| 5 | 7.5 |
| 12 | ? |
| 20 | ? |

To complete the table, we need to find the actual distances for the third and fourth rows.

Given that 2 inches represents 3 miles, we can set up a proportion to find the actual distances for the missing values:

2 inches / 3 miles = 12 inches / x miles

Cross-multiplying:

2x = 36

Dividing both sides by 2:

x = 18

So, for the third row, the actual distance is 18 miles.

Using the same method, we can find the actual distance for the fourth row:

2 inches / 3 miles = 20 inches / y miles

Cross-multiplying:

2y = 60

Dividing both sides by 2:

y = 30

So, for the fourth row, the actual distance is 30 miles.

The completed table is:

| Map Distance (in inches) | Actual Distance (in miles) |
|-------------------------|---------------------------|
| 2 | 3 |
| 5 | 7.5 |
| 12 | 18 |
| 20 | 30 |
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