Question

A cylindrical pipe is 36ft long and has a volumes of 100ft 3 whats is approximate diameter

Answer 1

The length (l) of the pipe = 36ft

The Volume(V) of the pipe = 100 ft³

The diameter(d) of the pipe = ?

`\begin{gathered} \text{ Volume (V) = }\pi r^2l \\ 100\text{ = 3.14 }* r^2*36 \\ r^2=(100)/(3.14*36)=0.8846 \\ r^2=0.8846 \\ r=\sqrt[]{0.8846\text{ }}\text{ =0.941 ft} \end{gathered}`

Diameter(d) of the pipe = 2 x radius

= 2 x 0.941 ft

= 1.882ft

Therefore, the approximate diameter of the pipe is 1.882ft to 3 decimal places.