Question

What would be the period of an oscillating spring that has a mass of 1.92 kg attached to it if the spring constant has a value of 0.800 N/m?15.1 s9.73s2.62 s4.06 s

Answer 1

Given:

The mass is m = 192 kg

The value of the spring constant is k = 0.8 N/m

To find the time period.

Step-by-step explanation:

The time period can be calculated by the formula

`T\text{ = 2}\pi\sqrt{(m)/(k)}`

On substituting the values, the time period will be

`\begin{gathered} T=2*3.14*\sqrt{(1.92)/(0.8)} \\ =9.73\text{ s} \end{gathered}`

Final Answer: The time period is 9.73 s