Question

How many atoms are in 0.0092g of gold

Answer 1

To find the number of atoms in 0.0092g of gold, we need to use the concept of molar mass and Avogadro's number. Therefore, there are approximately 2.81 x 10^19 atoms in 0.0092g of gold.

Step-by-step explanation:

To find the number of atoms in 0.0092g of gold, we need to use the concept of molar mass and Avogadro's number. First, we need to determine the molar mass of gold, which is 197g/mol. Next, we can use the following steps:

1. Convert the mass of gold to moles: 0.0092g / 197g/mol = 4.67 x 10^-5 mol
2. Use Avogadro's number (6.02 x 10^23) to convert moles to atoms: 4.67 x 10^-5 mol x 6.02 x 10^23 atoms/mol = 2.81 x 10^19 atoms

Therefore, there are approximately 2.81 x 10^19 atoms in 0.0092g of gold.