Question

A gas at pressure PN-m^-2 and temperature 27°C is heated to 77°C at constant volume.The new pressure is?

Answer 1

Given,

The initial pressure of the gas, P₁=P N/m²

The initial temperature of the gas, T₁=27 °C=300.15 K

The final temperature of the gas, T₂=77 °C=350.15 K

Let the new pressure of the gas be P₂

From Gay-Lussac's law,

`(P_1)/(T_1)=(P_2)/(T_2)`

On substituting the known values,

`\begin{gathered} (P)/(300.15)=(P_2)/(350.15) \\ \Rightarrow P_2=(P)/(300.15)*350.15 \\ P_2=1.17P \end{gathered}`

Therefore the new pressure will be 1.17 times the initial pressure, i.e., 1.17 P