Final answer:
The population of the bacteria colony on day 6 is 10,000 bacteria.
Step-by-step explanation:
To solve this problem, we can set up a proportion using the given information. We know that the population on day 4 is 5,000 and on day 8 is 52,000.
Let's set up the proportion:
4 days / 5,000 bacteria = 8 days / 52,000 bacteria
Cross-multiply and solve for the population on day 6:
4 * 52,000 = 8 * 5,000
208,000 = 40,000
Divide both sides of the equation by 4:
52,000 = 10,000
Therefore, the population of the colony on day 6 is 10,000 bacteria.