Question

Mercury (Hg) is an interesting element that much like the compound water, is a liquid at room temperature.

Mercury (Hg) freezes solid at -38.9 °C and boils at 357 °C.
Specific Heat (Hg) = 0.139 J/g °C
Heat of Fusion (Hg) = 11.4 J/g
Heat of Vaporization (Hg) = 296 J/g
How many kilojoules (kJ) of energy is required to fully melt 83.2 g of Mercury at -39.8 °C?

Answer 1

To fully melt 83.2 g of mercury at -39.8 °C, it would require approximately 0.94848 kilojoules (kJ) of energy.

Step-by-step explanation:

To calculate the amount of energy required to fully melt 83.2 g of mercury at -39.8 °C, we need to consider the heat of fusion. The heat of fusion is the amount of energy required to change a substance from a solid to a liquid without a change in temperature. In this case, the heat of fusion for mercury is given as 11.4 J/g.

Using the formula:

Energy = mass (g) × heat of fusion (J/g)

we can calculate the energy required as follows:

Energy = 83.2 g × 11.4 J/g = 948.48 J.

Since the question asks for the energy in kilojoules (kJ), we need to convert the answer from joules to kilojoules by dividing by 1000:

Energy = 948.48 J / 1000 = 0.94848 kJ.

Therefore, it would require approximately 0.94848 kilojoules (kJ) of energy to fully melt 83.2 g of Mercury at -39.8 °C.