Question

Write the linear equation that passes through the point (-6,1) with a slow of 1/2.

Answer 1

y = 1/2 x + 4

Step-by-step explanation:

The slope intercept form of an equation is

`y=mx+b`

where m is the slope and b is the y-intercept.

Now in our case the slope m = 1/2; therefore,

`y=(1)/(2)x+b`

Now we just need to find the value of b.

Luckily we are told that the line passes through the point (-6, 1), which means that the above equation must satisfy x = -6 given y = 1.

Putting in x = -6 and y = 1 in the above equation gives

`1=(1)/(2)(-6)+b`

which simplifies to give

`1=-3+b`

adding 3 to both sides gives

`\begin{gathered} 1+3=-3+b+3 \\ 4=b \end{gathered}`

Hence, the value of b is 4, and therefore, our equation becomes

`\boxed{y=(1)/(2)x+4}`

which is our answer!