Final answer:
The frequency of oscillations for a block attached to a spring with a mass of 0.94 kg and a spring constant of 372 N/m is approximately 3.167 Hz.
Step-by-step explanation:
To calculate the frequency of oscillations for a block attached to a spring, we use the formula for the frequency of a mass-spring system, given as № = 1 / (2π) ∙ √(k/m), where k is the spring constant and m is the mass of the object. Plugging in the values given in the question, with a spring constant (k) of 372 N/m and a mass (m) of 0.94 kg, the frequency № is calculated as follows:
№ = 1 / (2π) ∙ √(372 N/m / 0.94 kg)
№ ≈ 1 / (2π) ∙ √(395.7447 s⁻²)
№ ≈ 1 / (2π) ∙ √ • (19.8931 s⁻¹)
№ ≈ 1 / (6.2832) ∙ 19.8931 s⁻¹
№ ≈ 3.167 Hz
Therefore, the frequency of the oscillations is approximately 3.167 Hz.