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What is the harmonic mean of the sample sizes required to achieve a power of 0.80 for the coach's experiment with a significance level of 0.05 and a large effect size (d = 0.80)?

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Final answer:

The harmonic mean of the required sample sizes for the coach's experiment is equal to the sample size.

Step-by-step explanation:

The harmonic mean of the sample sizes required to achieve a power of 0.80 for the coach's experiment can be calculated using the formula:

Harmonic mean = 2 / (1/n1 + 1/n2)

Where n1 and n2 are the sample sizes of the two groups being compared.

In this case, since only one effect size (d = 0.80) is given, we can assume that the sample sizes of the two groups are the same.

Substituting the given values into the formula:

Harmonic mean = 2 / (1/n + 1/n) = 2 / (2/n) = 2n/2 = n

Therefore, the harmonic mean of the required sample sizes is n.

User Abhishek Kaushik
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