Final answer:
The first ionization energy of lithium is used to calculate the frequency and wavelength of photons capable of ionizing it. By applying the equations E = hf and c = λf, we can determine the frequency and wavelength of the photons.
Step-by-step explanation:
The first ionization energy of a lithium atom is 0.86 atomic units (aj). To calculate the frequency and wavelength of photons capable of ionizing just lithium, we need to use the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J·s), and f is the frequency of the photon. First, we convert the ionization energy of lithium to joules by multiplying it by 3.104 x 10^-18 J/aj. Then, we use the equation E = hf to solve for the frequency f. Rearranging the equation gives f = E/h. Plugging in the value for E and h, we can calculate the frequency. Next, we can use the equation c = λf, where c is the speed of light (3 x 10^8 m/s), λ is the wavelength, and f is the frequency, to solve for the wavelength λ. Rearranging the equation gives λ = c/f. Plugging in the value for c and the calculated value for f, we can calculate the wavelength. Therefore, the frequency and wavelength of photons capable of ionizing just lithium are [insert calculated values for frequency and wavelength].