208k views
4 votes
The 1st and 3rd term of a GP are 5 and 80 respectively, what is the 4th term

User Jash Shah
by
9.2k points

1 Answer

5 votes

Final answer:

To find the 4th term of a GP with the 1st term of 5 and the 3rd term of 80, we first determined the common ratio to be 4. Then, using the common ratio, we calculated the 4th term to be 320.

Step-by-step explanation:

To find the 4th term of a geometric progression (GP) when the 1st and 3rd terms are given as 5 and 80, respectively, we first need to find the common ratio of the progression.



We know that in a GP, the nth term is given by an = a1 × r(n-1), where a1 is the first term and r is the common ratio.



Given that the 3rd term a3 is 80, we can use the formula to write a3 = a1 × r(3-1) = 5r2, and thus:

r = √(80/5) = √(16) = 4.



Now, to find the 4th term (a4), we use the common ratio r = 4 and the first term a1 = 5:



a4 = a1 × r(4-1) = 5 × 43 = 5 × 64 = 320.



Therefore, the 4th term of the GP is 320.

User Karandeep
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories