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The initial velocity of a body is 5.20m/s. What is its velocity after 2.50s if it accelerates uniformly at 3.00m/s²?

User Ben Newton
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1 Answer

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Final answer:

To calculate the velocity after 2.50 seconds, use the equation v = v0 + at, which yields a final velocity of 12.70 m/s for a body with an initial velocity of 5.20 m/s and an acceleration of 3.00 m/s².

Step-by-step explanation:

The initial velocity of a body is 5.20 m/s and its acceleration is 3.00 m/s² over a period of 2.50 s. To calculate the velocity after 2.50 s, we can use the kinematic equation for motion, which expresses the final velocity (v) in terms of the initial velocity (v0), acceleration (a), and time (t), given by the formula:

v = v0 + at.

Plugging in the values we have:

v = 5.20 m/s + (3.00 m/s² × 2.50 s)

v = 5.20 m/s + 7.50 m/s

v = 12.70 m/s

Therefore, the final velocity of the body after 2.50 seconds is 12.70 m/s.

User Chirag Ghori
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