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The average height of a woman aged 20–74 years is 64 inches in 2002, with an increase of approximately one inch from 1960. Suppose the height of a woman is normally distributed with a standard deviation of 2 inches. (a) What is the probability that a randomly selected woman in this population is between 58 inches and 70 inches? (b) What are the quartiles of this distribution? (c) Determine the height that is symmetric about the mean that includes 90?

User Dreamcrash
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Final answer:

To address the questions posed by the student, one must calculate the Z-scores for the given heights, refer to the standard normal distribution to determine corresponding probabilities, and use these to calculate the probability of a variable falling within a certain range, as well as identifying the quartiles and specific height percentiles.

Step-by-step explanation:

The student's question is about calculating probabilities and quartiles for normally distributed variables. For a normally distributed variable X with a known mean and standard deviation, one can calculate the probability of X falling within a specified range using the standard normal distribution (Z-score).

Probability Calculation

To find the probability of a randomly chosen Asian adult male being between 65 and 69 inches tall:

  • Calculate the Z-scores for 65 and 69 inches.
  • Use the standard normal distribution table to find the probability corresponding to these Z-scores.
  • The desired probability is the difference between these two probabilities.

Understanding Normal Distribution

In terms of meeting Asian adult males taller than 72 inches, we would calculate the Z-score for 72 inches and use the standard normal distribution table to determine the probability of a male being taller than 72 inches. Since the mean height is 66 inches with a standard deviation of 2.5 inches, a height of 72 inches is quite far from the mean, leading us to expect that very few males will be taller than this height.

Quartiles and Percentiles

The quartiles of a normal distribution divide the distribution into four equal parts. You would use the Z-scores corresponding to the 25th percentile (Q1) and the 75th percentile (Q3) to find these values. The middle 40 percent of heights would involve finding the Z-scores for the 30th and 70th percentiles and then converting these back to actual heights.

User Pradip Karki
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