Final answer:
Calculate the amount of precipitated Cu(OH)₂ by converting the provided mass of limiting reactant CuSO₄ to moles, and then use stoichiometry to determine the theoretical yield in grams of Cu(OH)₂. To calculate percent yield, divide the actual yield by the theoretical yield and multiply by 100, but the actual yield is not given here.
Step-by-step explanation:
To determine how many grams of Cu(OH)₂ should precipitate out in the reaction using the limiting reagent, you first need to calculate the theoretical yield based on the amount of copper sulfate (CuSO₄), which is the limiting reactant. Convert the mass of CuSO₄ to moles using its molar mass (159.62 g/mol), and then use stoichiometry to find the moles of Cu(OH)₂. Next, calculate the molar mass of Cu(OH)₂, which is 97.57 g/mol. Multiply the moles of Cu(OH)₂ by its molar mass to find the theoretical yield in grams.
To find the percent yield, you'd take the actual yield from the experiment and divide it by the theoretical yield, then multiply by 100. However, the actual yield is not provided in the question, so the percent yield cannot be calculated in this instance.