Question

When an athlete throws a javelin, its height above the ground when it has travelled a horizontal distance of x m is given by h(x) = 0.015x² * x¹.⁷ meters. What is the height of the javelin when it has travelled a horizontal distance of 5 meters?

1) 0.1875 meters
2) 0.375 meters
3) 0.9375 meters
4) 1.875 meters

Answer 1

The height of the javelin when it has traveled a horizontal distance of 5 meters is 0.9375 meters.

Step-by-step explanation:

To find the height of the javelin when it has traveled a horizontal distance of 5 meters, we can substitute x=5 into the equation h(x) = 0.015x² * x¹.⁷.

So, h(5) = 0.015(5)² * (5¹.⁷).

Calculating this gives us h(5) = 0.015(25) * (27.893).

Simplifying further, h(5) = 0.9375.

Therefore, the height of the javelin when it has traveled a horizontal distance of 5 meters is 0.9375 meters.