Final answer:
The combustion of the benzene sample produced 39.1 kJ of heat.
Step-by-step explanation:
To find the heat produced by the combustion of the benzene sample, we need to calculate the total heat absorbed by the bomb calorimeter and the water it is submerged in.
The heat capacity of the bomb calorimeter is 784 J/°C, and the temperature increase of the calorimeter is 8.39 °C. So, the heat absorbed by the bomb calorimeter is:
Heat absorbed = (Heat capacity) * (Temperature change)
= 784 J/°C * 8.39 °C = 6562.76 J
Next, we need to calculate the heat absorbed by the water. We can use the formula:
Heat absorbed by water = (Mass of water) * (Specific heat of water) * (Temperature change)
The mass of water is 925 mL, which is equivalent to 925 g. The specific heat of water is 4.18 J/g°C. So:
Heat absorbed by water = 925 g * 4.18 J/g°C * 8.39°C = 32535.575 J
The total heat absorbed is the sum of the heat absorbed by the calorimeter and the water:
Total heat absorbed = Heat absorbed by bomb calorimeter + Heat absorbed by water
= 6562.76 J + 32535.575 J = 39100.335 J = 39.1 kJ
Therefore, the combustion of the benzene sample produced 39.1 kJ of heat.