Question

What volume of 7.50 M HNO₃ should be diluted to prepare 25.00 mL of a 2.00 M HNO₃ solution?

1) 0.150 mL
2) 9.38 mL
3) 6.67 mL
4) 0.107 mL
5) I don't know yet

Answer 1

To dilute 7.50 M HNO₃ to obtain 25.00 mL of 2.00 M HNO₃ solution, 6.67 mL of the concentrated acid is required. The calculation is based on the dilution equation M1V1 = M2V2.

Step-by-step explanation:

To find the volume of 7.50 M HNO₃ that should be diluted to prepare 25.00 mL of a 2.00 M HNO₃ solution, you can use the dilution equation M₁V₁ = M₂V₂, where M₁ and V₁ are the molarity and volume of the concentrated solution and M₂ and V₂ are the molarity and volume of the diluted solution.

Insert the known values into the equation:
7.50 M × V₁ = 2.00 M × 25.00 mL

Solve for V₁:
V₁ = (2.00 M × 25.00 mL) / 7.50 M

V₁ = 50.00 mL / 7.50 M

V₁ = 6.67 mL

Therefore, you would need 6.67 mL of 7.50 M HNO₃ to prepare 25.00 mL of a 2.00 M HNO₃ solution. The correct answer from the options provided is 3) 6.67 mL.