Question

What volume (in l) of a 1.0 M Fe(NO₃)₃ solution can be diluted to prepare 1.00 L of a solution with a concentration of 0.15 M?

Answer 1

To prepare 1.00 L of a 0.15 M Fe(NO3)3 solution from a 1.0 M solution, 150 mL of the concentrated solution is required according to the dilution equation M1V1 = M2V2.

Step-by-step explanation:

To determine the volume of a 1.0 M Fe(NO3)3 solution needed to prepare 1.00 L of a 0.15 M solution, we use the concept of dilution. The dilution equation is M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution. Substituting the given values into the equation:

M1V1 = M2V2
1.0 M × V1 = 0.15 M × 1.00 L

Rearranging for V1 gives us:

V1 = (0.15 M × 1.00 L) / 1.0 M
V1 = 0.15 L or 150 mL

Therefore, 150 mL of the 1.0 M Fe(NO3)3 solution is needed to prepare 1.00 L of a 0.15 M Fe(NO3)3 solution.