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Two friends are standing 200 m apart. One friend starts moving at a speed of 15 m/s and the other friend starts moving at a speed of 10 m/s. When and where will they meet?

User Savedario
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1 Answer

3 votes

Final answer:

The two friends will meet after 13.33 seconds, with one friend approximately 199.95 meters away from the starting point and the other friend approximately 133.3 meters away.

Step-by-step explanation:

To find when and where the two friends will meet, we need to calculate the time it takes for each friend to travel the distance and then use that time to find their positions. Let's start by finding the time it takes for each friend to travel 200 m:

Friend 1: Time = Distance / Speed = 200 m / 15 m/s = 13.33 s

Friend 2: Time = Distance / Speed = 200 m / 10 m/s = 20 s

Since Friend 1 takes 13.33 s and Friend 2 takes 20 s, they will meet after 13.33 s.

Now, let's find their positions when they meet:

Friend 1: Distance = Speed × Time = 15 m/s × 13.33 s = 199.95 m

Friend 2: Distance = Speed × Time = 10 m/s × 13.33 s = 133.3 m

Therefore, they will meet after 13.33 seconds, and Friend 1 will be approximately 199.95 meters away from the starting point, while Friend 2 will be approximately 133.3 meters away.

User Will Oldham
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