Final answer:
The mass of water that will change its temperature by 30°C when 525 J of heat is added is approximately 4.19 grams, calculated using the heat equation formula.
Step-by-step explanation:
To determine the mass of water that would change its temperature by 30°C when 525 J of heat is added, we can use the formula Q = mcΔT, where Q is the heat added in joules, m is the mass of the substance in kilograms, c is the specific heat capacity (for water it's approximately 4.18 J/g°C), and ΔT is the change in temperature.
First, we rearrange the formula to solve for m:
m = Q / (cΔT)
Then we plug in the values given:
m = 525 J / (4.18 J/g°C × 30°C)
After calculating, we find the mass of the water:
m = 525 J / (125.4 J/°C)
m ≈ 4.19 g
Therefore, the mass of the water that will change its temperature by 30°C when 525 J of heat is added is approximately 4.19 grams.