Question

Transformer suppose the voltage in the primary coil is 600 v and the voltage in the secondary coil is 150 v. If there are 36 loops in the primary coil, how many loops are in the secondary coil?

Answer 1

The number of loops in the secondary coil of the transformer is calculated using the transformer equation which states that the ratio of the secondary voltage to the primary voltage equals the ratio of the number of secondary turns to primary turns. With a primary voltage of 600 V and secondary voltage of 150 V, and 36 loops in the primary, the secondary has 9 loops.

Step-by-step explanation:

This concerns the workings of a transformer and specifically involves the calculation of the number of turns in the secondary coil based on the number of turns in the primary coil and the input and output voltages. The transformer equation is used to find the relationship between primary and secondary voltages and coil turns. According to the transformer equation, the ratio of the secondary to primary voltages equals the ratio of the number of loops in their coils. So, using the equation: Vp/Vs = Np/Ns. where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of primary turns, and Ns is the number of secondary turns. Therefore, we can rearrange and solve for Ns: Ns = (Vs/Vp) × Np = (150V / 600V) × 36 loops. Ns = 0.25 × 36 loops = 9 loops. Hence, there are 9 loops in the secondary coil of the transformer.