Final answer:
The tension in the left-hand wire is 80 N.
Step-by-step explanation:
To find the tension in the left-hand wire, we can start by considering the forces acting on the wooden board. Since the board is being carried by two people, the weight of the board is balanced by the tension in both wires. Let's call the tension in the left-hand wire TL and the tension in the right-hand wire TR. The total weight of the board is 160 N, so the tension in the left-hand wire must be equal to half of that, which is 80 N.To find the tension in the left-hand wire, you would set up an equation where the total counterclockwise moments equal the total clockwise moments. If the tension is different in the left and right wires, the location where each force acts will impact the solution. For example, if another force acts on different parts of the board, such as a person standing on it or additional weight being hung from it, this will affect the tension in the wires differently depending on where these forces are applied.