Question

In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .

Answer 1

74.0°

Explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

`(a)/(sin(A))=(b)/(sin(B))=(c)/(sin(C))`

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

`(k)/(sin(K))=(j)/(sin(J)) \\\\(4.1)/(sin(K))=(3.8)/(sin(63)) \\\\sin(K)=(4.1*sin(63))/(3.8)\\\\sin(K)=0.9613\\\\K=sin^(-1) (0.9613)\\\\K=74.0^o \\`