Final answer:
The probability of selecting a plate with 'abc123' or '123abc' from 14,781,600 plates is 2/14,781,600, as these are two distinct favorable outcomes in a set of equally likely outcomes.
Step-by-step explanation:
The question asks about the probability of selecting a specific plate from a total of 14,781,600 plates. Assuming that each plate has an equal chance of being selected, we can calculate the probability by recognizing that there are two favorable outcomes ('abc123' and '123abc') out of the 14,781,600 possible outcomes. Therefore, the probability for each specific plate is 1/14,781,600. To find the total probability for either of these two specific plates, we add their individual probabilities together since they are mutually exclusive events. The calculation is as follows:
- P(abc123 or 123abc) = P(abc123) + P(123abc)
- P(abc123 or 123abc) = 1/14,781,600 + 1/14,781,600
- P(abc123 or 123abc) = 2/14,781,600
Resulting in a probability of 2/14,781,600.