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What is the energy difference between the spin state of h 1 nuclei in a magnetic field of 5.87t?

User Unchosen
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Final answer:

The energy difference between the spin states of hydrogen-1 nuclei in a magnetic field can be calculated using the formula ΔE = γB, where ΔE is the energy difference, γ is the gyromagnetic ratio, and B is the magnetic field strength. For hydrogen-1 nuclei, the gyromagnetic ratio is approximately 42.58 MHz/T. Therefore, if the magnetic field strength is 5.87 T, the energy difference between the spin states of the nuclei would be 250.03 MHz.

Step-by-step explanation:

The energy difference between the spin states of hydrogen-1 nuclei in a magnetic field can be calculated using the formula:

ΔE = γB

Where ΔE is the energy difference, γ is the gyromagnetic ratio, and B is the magnetic field strength.

For hydrogen-1 nuclei, the gyromagnetic ratio is approximately 42.58 MHz/T. Therefore, if the magnetic field strength is 5.87 T, the energy difference between the spin states of the nuclei would be:

ΔE = 42.58 MHz/T × 5.87 T = 250.03 MHz

User Shehram Tahir
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