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What is the osmotic pressure (in atm) of a 1.36m aqueous solution?

User RaamEE
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Final answer:

To calculate the osmotic pressure of a 1.36m solution, you use the formula II = MRT with the values M = 1.36 mol/L, R = 0.0821 L·atm/(K·mol), and T = 298 K (assuming a temperature of 25°C).

Step-by-step explanation:

The osmotic pressure of a solution can be calculated using the formula II = MRT, where II is the osmotic pressure, M is the molarity of the solution, R is the universal gas constant (0.0821 L·atm/(K·mol)), and T is the temperature in kelvin (K). For the given 1.36m (molal) solution, to find osmotic pressure we must assume a density of 1 kg/L to approximate the molarity as molality and molarity are not equivalent. Assuming the temperature is 25°C (or 298 K since 25°C + 273 = 298 K), the calculation for the osmotic pressure would be (1.36 mol/L) × (0.0821 L·atm/(K·mol)) × (298 K).

User Xavier Falempin
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