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What is the specific latent heat of a 10.0mg object that transfers 740mj during a change of state?

User Autra
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Final answer:

The specific latent heat of a 10.0 mg object that transfers 740 mJ during a change of state is 74,000,000 J/g after converting the mass to grams and the energy transferred to joules and then applying the formula Q = mL.

Step-by-step explanation:

The specific latent heat of an object can be calculated using the formula Q = mL, where Q is the heat transferred, m is the mass of the object, and L is the specific latent heat.

To find the specific latent heat for a 10.0 mg object that transfers 740 mJ during a change of state, first we need to convert units so they match. Since 10 mg is equal to 0.01 g and 740 mJ is equal to 740,000 J, we can rewrite Q as 740,000 J and m as 0.01 g. Inserting these values into the formula and solving for L gives us L = Q/m = 740,000 J / 0.01 g = 74,000,000 J/g.

This means the specific latent heat of the object is 74,000,000 J/g.

User Zeph
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