Final answer:
The maximum amount of S8 that can be produced by combining 75.0 g of each reactant is 0.292 mol.
Step-by-step explanation:
To determine the maximum amount of S8 that can be produced by combining 75.0 g of each reactant, we need to calculate the moles of starting reactants and determine the limiting reactant. The balanced equation shows that the ratio between Sn and S8 is 1:1, so the moles of Sn will be equal to the moles of S8. We can use the molar mass of Sn and S8 to calculate the moles of each reactant.
Molar mass of Sn = 118.71 g/mol
Molar mass of S8 = 256.52 g/mol
Moles of Sn = 75.0 g / 118.71 g/mol = 0.632 mol
Moles of S8 = 75.0 g / 256.52 g/mol = 0.292 mol
Since the ratio between Sn and S8 is 1:1, S8 is the limiting reactant. Therefore, the maximum amount of S8 that can be produced is 0.292 mol.