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What is the equiLiBrium constant for the following reaction if the concentrations of the reactants are 0.747 M, 0.771 M, and the concentrations of the products are 1.307 M and 1.848 M?

User Yivi
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1 Answer

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Final answer:

The equilibrium constant for the given reaction is 2.119.

Step-by-step explanation:

The equilibrium constant for a reaction is a measure of the extent to which a reaction proceeds. It is calculated by comparing the concentrations of the products to the concentrations of the reactants at equilibrium. In this case, the equilibrium constant can be calculated using the following equation:



Kc = ([C]product1) * ([C]product2) / ([C]reactant1) * ([C]reactant2)



Substituting the given concentrations into the equation, we have:



Kc = (1.307) * (1.848) / (0.747) * (0.771)



Simplifying the expression gives us the equilibrium constant:



Kc = 2.119

User Stewart Ellis
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