184k views
4 votes
What is the equation of the parabola with vertex at (-2, 3) that passes through (0, 8)?

User IxM
by
8.7k points

1 Answer

6 votes

Final answer:

The equation of the parabola with vertex at (-2, 3) that passes through (0, 8) is y = (5/4)(x + 2)^2 + 3.

Step-by-step explanation:

The equation of a parabola can be written in the standard form y = ax^2 + bx + c, where a, b, and c are coefficients and the vertex form is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.

To find the specific equation of the parabola with a vertex at (-2, 3) that passes through the point (0, 8), we first use the vertex form. The general equation becomes y = a(x + 2)^2 + 3, since the vertex (h, k) is (-2, 3). We can determine the value of a by substituting the point (0, 8) into the equation: 8 = a(0 + 2)^2 + 3. Simplifying this, we get 5 = 4a, therefore a = 5/4.

The final equation of the parabola is y = (5/4)(x + 2)^2 + 3.

User AFHood
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories