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Write the equation in standard form of the line that passes through the point (2,8) and has a slope of 3/2?

User Carasel
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1 Answer

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Final answer:

To determine the equation of the line in standard form, we start with the point-slope equation, substitute the given point and slope, convert to slope-intercept form, and then rearrange into standard form to obtain -3x + 2y = 14.

Step-by-step explanation:

To write the equation of the line that passes through the point (2,8) with a slope of 3/2 in standard form, we follow these steps:

  1. Start with the point-slope form of a line: y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point through which the line passes.
  2. Substitute the known values: y - 8 = ¾(x - 2).
  3. Rearrange the equation to the slope-intercept form y = mx + b, yielding y = ¾ x + 7.
  4. Convert the slope-intercept form to standard form (Ax + By = C) by clearing the fraction and moving all terms to one side: 2y = 3x + 14, then -3x + 2y = 14.

Therefore, the standard form of the equation is -3x + 2y = 14.

User Waltur Buerk
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