Final answer:
The balanced equation for the reaction between lead(II) acetate and ammonium iodide, forming solid lead(II) iodide and aqueous ammonium acetate, is Pb(CH3CO2)2 (s) + 2 NH4I (aq) → PbI2 (s) + 2 NH4CH3CO2 (aq).
Step-by-step explanation:
The question asks for the balanced chemical equation for the reaction between solid lead(II) acetate and an aqueous solution of ammonium iodide. When these two solutions mix, a precipitation reaction occurs, forming solid lead(II) iodide and aqueous ammonium acetate.
The balanced chemical equation for this reaction is:
Pb(CH₃CO₂)2 (s) + 2 NH4I (aq) → PbI2 (s) + 2 NH4CH₃CO₂ (aq)
This equation illustrates the concept of double displacement reactions where the cations and anions in the reactants exchange partners to form new products.