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The weights of oranges are normally distributed with a mean of 12.4 pounds and a standard deviation of 3 pounds. Find the minimum weight that would be included in the top 5

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Final answer:

To find the minimum weight included in the top 5% of the distribution, use the z-score formula and a z-table or calculator to find the corresponding z-value. Then, rearrange the z-score formula to solve for the minimum weight.

Step-by-step explanation:

To find the minimum weight that would be included in the top 5%, we need to find the z-score that corresponds to the top 5% of the normal distribution. The z-score represents the number of standard deviations a particular value is from the mean. We can use the z-score formula:

z = (x - mean) / standard deviation

To find the z-score for the top 5%, we look up the corresponding z-value in the z-table or use a calculator. In this case, the z-value for the top 5% is approximately 1.645.

Now, we can solve for the minimum weight by rearranging the z-score formula:

x = mean + (z * standard deviation)

Plugging in the values, we have:

x = 12.4 + (1.645 * 3) ≈ 17.935

Therefore, the minimum weight that would be included in the top 5% is approximately 17.935 pounds.

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