Question

Put a point on the line. The graph shows a coordinate plane that goes from negative 8 to 8 on the horizontal axis and negative 4 to 12 on the vertical axis. The graph also shows a line with an x-intercept of -4.5 and a y-intercept of 9. Type an ordered pair to put a point on this line.

Answer 1

To place a point on the line with a slope of 3 and a y-intercept of 9, you can start at (0,9) and move one unit to the right to x=1 and then up 3 units in y to get the point (1,12).

Step-by-step explanation:

To put a point on the line with an x-intercept of -4.5 and a y-intercept of 9, we can use the slope information provided. The slope of the line is given as 3, which means the line rises 3 units on the y-axis for every 1 unit it moves to the right on the x-axis. With this information, we can choose any x-value, and use the slope to find the corresponding y-value.

Since we know the line passes through the y-intercept at (0,9), we can move 1 unit to the right (x increases by 1) and go up 3 units (since the slope is 3) to find another point. For example, if we start at the y-intercept (0,9) and move 1 unit to the right, our x-coordinate is now 1. We then move up 3 units on the y-axis to get the y-coordinate, which will be 9 + 3 = 12. So, a point on the line is (1,12).