Question

Porter is sitting in a bucket of a ferris wheel with a 53-foot radius at the 3 o'clock position. The ferris wheel begins to move counter clockwise. What is the angle of rotation when Porter is 35 feet above the ferris wheel's center?

Answer 1

To find the angle of rotation when Porter is 35 feet above the ferris wheel's center, we can use trigonometry. The angle is approximately 34.46 degrees.

Step-by-step explanation:

To find the angle of rotation when Porter is 35 feet above the ferris wheel's center, we can use trigonometry. Let's consider a right triangle where the hypotenuse is the radius of the ferris wheel, the opposite side is the height above the center (35 feet), and the adjacent side is the distance from the center to Porter's position at the 3 o'clock position (53 feet).

Using the tangent function, we can calculate the angle:

tan(θ) = opposite/adjacent

tan(θ) = 35/53

Using an inverse tangent function (or arctan) on both sides, we can find the angle:

θ = arctan(35/53)

Using a calculator, we can find that the angle is approximately 34.46 degrees.