Problem
How many solutions does the following equation have? 4(y+z+ 2) = sqrt(16) (2+ y)
Solution
For this case the first step would be distribute the terms in the equation and we got:
4y +4z +8 = 8 +4y
We can subtract in both sides 4y and we got:
4z +8= 8
Then we can subtract 8 in both sides and we got:
4z = 0
z=0
Then if z=0 y can be any number so then we have infinite solutions for this case
Infinite