Question

Parker is pulling his 6 kg blue wagon on a sidewalk with a constant velocity using a force of 25 N. There are four forces acting on the wagon. Determine the value for each force.

Answer 1

The value for each force acting on the wagon is Parker's force = 25 N, weight of the wagon = 58.8 N, normal force = 58.8 N, and force of friction = 25 N.

Step-by-step explanation:

To determine the value for each force acting on the wagon, we need to consider the forces involved. The force exerted by Parker is 25 N, the weight of the wagon is 6 kg * 9.8 m/s^2 = 58.8 N, and the normal force exerted by the ground is equal to the weight of the wagon, which is 58.8 N. Since the wagon is moving with a constant velocity, the force of friction must be equal to the force exerted by Parker, which is 25 N. Therefore, the value for each force acting on the wagon is: Parker's force = 25 N, weight of the wagon = 58.8 N, normal force = 58.8 N, and force of friction = 25 N.