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Suppose you mix 25.0 ml of .234m feCl₃ solution with 42.5 ml of .453m NaOH?

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Final answer:

The question deals with a chemical reaction involving FeCl3 and NaOH, where stoichiometry and molarity are used to analyze the precipitation reaction and determine the outcome of mixing these solutions.

Step-by-step explanation:

The question involves a chemical reaction between an iron(III) chloride solution (FeCl3) and a sodium hydroxide solution (NaOH). When these solutions are mixed, a precipitation reaction occurs, forming solid iron(III) hydroxide and sodium chloride in solution. To analyze such a reaction, one would typically use stoichiometry and the concept of molarity to find the number of moles, and from there, determine the precipitate mass or concentration of resulting solutions.

Given the provided context, if we wish to calculate the exact outcome of the reaction mentioned in the question, we would use the following steps.

  1. Write the balanced chemical equation for the reaction: FeCl3 + 3NaOHFe(OH)3 + 3NaCl.
  2. Calculate the number of moles of FeCl3 and NaOH using the given volume and molarity.
  3. Determine the limiting reactant which will dictate the amount of precipitate formed.
  4. Use stoichiometry to relate the moles of limiting reactant to moles of the products formed.
  5. If necessary, calculate the concentration of the remaining aqueous ions or the mass of the precipitate produced.

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