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Solve the following system of equations: x - 2y = 18, 4x + 3y = -16?

User Gigz
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Final answer:

To solve the system of equations x - 2y = 18 and 4x + 3y = -16, we can use the method of elimination. Multiply the first equation by 2 and the second equation by 3 to make the coefficients of y equal in both equations. Add the two equations together to obtain a new equation relating x and y. Solve this equation and substitute the value back into one of the original equations to find the other variable.

Step-by-step explanation:

To solve the system of equations x - 2y = 18 and 4x + 3y = -16, we can use the method of substitution or elimination. Let's use the method of elimination:

Multiply the first equation by 2 to make the coefficients of y in both equations equal: 2(x - 2y) = 2(18) becomes 2x - 4y = 36.
Multiply the second equation by 3 to make the coefficients of y in both equations equal: 3(4x + 3y) = 3(-16) becomes 12x + 9y = -48.

Add the two equations together:
(2x - 4y) + (12x + 9y) = 36 + (-48)
14x + 5y = -12.

Now we have a new equation that relates x and y. We can solve this equation for either variable and substitute the value back into one of the original equations to find the other variable.

I hope this helps! Let me know if you have any further questions.

User Dmitry R
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