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What is the maximum height of h=-16t²+32t+4

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Final answer:

The maximum height of the equation h = -16t² + 32t + 4 can be found using calculus. The maximum height is 52 feet.

Step-by-step explanation:

The maximum height of the equation h = -16t² + 32t + 4 can be found using calculus. This equation represents the height of an object at a given time t with respect to gravity. To find the maximum height, we need to find the vertex of the quadratic equation.

The vertex of a quadratic equation of the form ax² + bx + c is given by the formula t = -b/2a. In this case, a = -16, b = 32, and c = 4. Substituting these values into the formula, we get t = -32/2(-16) = 1 second.

Substituting this value of t back into the equation, we find h = -16(1)² + 32(1) + 4 = 16 + 32 + 4 = 52 feet. Therefore, the maximum height of the equation is 52 feet.

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