Final answer:
The final concentration of a CuSO₄ solution diluted from 6.00 mL of 0.0250 M to 10 mL is calculated using the dilution equation C1V1 = C2V2, resulting in a final concentration of 0.0150 M.
Step-by-step explanation:
The subject of this question relates to the calculation of final concentration after dilution in Chemistry. When a solution is diluted, its concentration decreases while the number of moles of solute remains constant. This is represented by the equationC1V1 = C2V2 , where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume, respectively.
In this particular case, we use the dilution equation to find the final concentration of the CuSO₄ solution after dilution. We are given that 6.00 mL of a 0.0250 M CuSO₄ solution is diluted to 10 mL. Using the dilution formula, we can calculate:
C2 =( C1V1 ) /V2 =( 0.0250 M* 6.00 ML ) / 10 ML = 0.0150 M. Therefore, the final concentration of the CuSO₄ solution after dilution is 0.0150 M.