Question

If 35 g of CH₃OH are dissolved in 500ml of solution, what is the concentration of CH₃OH in the solution?

Answer 1

To find the concentration of CH₃OH, divide the mass of CH₃OH by its molar mass to get moles, convert the volume to liters, and then divide moles by volume to get molarity. The concentration of CH₃OH is 2.184 M.

Step-by-step explanation:

To calculate the concentration of CH₃OH in the solution, we need to use the formula for molarity, which is the number of moles of solute per liter of solution (mol/L). The steps are as follows:

1. First, calculate the number of moles of CH₃OH using its molar mass. The molar mass of CH₃OH (methanol) is approximately 32.04 g/mol.
   
2. Next, divide the mass of CH₃OH by its molar mass to find the number of moles:
   Number of moles = 35 g ÷ 32.04 g/mol = 1.092 moles (approximately).
   
3. Since the volume of the solution is given in milliliters, convert it to liters:
   500 mL = 0.500 L.
   
4. Finally, divide the number of moles by the volume in liters to find the molarity:
   Molarity = 1.092 moles ÷ 0.500 L = 2.184 M (to three significant figures).

The concentration of CH₃OH in the solution is 2.184 M.