1 Answer

Igor Alemasow · Answer 1 · 2023-01-26T02:52:08+0000

we have that

the area of the figure is equal to the area of a right triangle plus the area of a semicircle

so

$A=(1)/(2)\cdot b\cdot h+(1)/(2)\cdot\pi\cdot r^2$

where

Applying Pythagorean Theorem

Find out the base of the triangle

5^2=4^2+b^2

b^2=25-16

b^2=9

b=3 in

h=4 in

r=2 in

substitute given values

$A=(1)/(2)\cdot3\cdot4+(1)/(2)\cdot\pi\cdot2^2$

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