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If 21.5 mol of an ideal gas occupies 66.5 l at 429 k, what is the pressure of the gas?

User Terence
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Final answer:

To find the pressure of the gas, we can use the ideal gas law equation: PV = nRT. Plugging in the given values, we can calculate the pressure to be approximately 111.34 atm.

Step-by-step explanation:

To find the pressure of the gas, we can use the ideal gas law equation: PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

Given: n = 21.5 mol, V = 66.5 L, and T = 429 K.

Plugging in these values, we can solve for P:

P = (nRT) / V = (21.5 mol)(0.0821 L·atm/mol·K)(429 K) / 66.5 L ≈ 111.34 atm

Therefore, the pressure of the gas is approximately 111.34 atm.

User Abdulaziz Noor
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