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How much work (in j) is involved in a chemical reaction if the volume decreases from 4.40 to 1.55 l against a constant pressure of 0.837 atm?

User Yogsototh
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1 Answer

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Final answer:

The work done in a chemical reaction can be calculated using the equation: work = -PΔV, where P is the pressure and ΔV is the change in volume. In this specific case, the amount of work involved in the chemical reaction is 1.731 J.

Step-by-step explanation:

The work done in a chemical reaction can be calculated using the equation: work = -PΔV, where P is the pressure and ΔV is the change in volume. In this case, the volume decreases from 4.40 L to 1.55 L against a constant pressure of 0.837 atm.

To calculate the work, use the formula:

work = -P × (V₂ - V₁)

Substituting the given values into the equation:

work = -0.837 atm × (1.55 L - 4.40 L)

work = 1.731 J

Therefore, the amount of work involved in the chemical reaction is 1.731 J.

User Isaac Waller
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